3x^2+10x=-16

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Solution for 3x^2+10x=-16 equation: 



3x^2+10x=-16

We move all terms to the left:

3x^2+10x-(-16)=0

We add all the numbers together, and all the variables

3x^2+10x+16=0

a = 3; b = 10; c = +16;
Δ = b2-4ac
Δ = 102-4·3·16
Δ = -92
Delta is less than zero, so there is no solution for the equation

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